7/x+3-5/x-3=3x/x^2-9

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Solution for 7/x+3-5/x-3=3x/x^2-9 equation: 


D( x )

x = 0

x^2 = 0

x = 0

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

7/x-(5/x)-3+3 = (3*x)/(x^2)-9 // - (3*x)/(x^2)-9

7/x-(5/x)-((3*x)/(x^2))-3+3+9 = 0

7/x-5*x^-1-3*x^-1-3+3+9 = 0

-1*x^-1 = -9 // : -1

x^-1 = 9

-1 < 0

1/(x^1) = 9 // * x^1

1 = 9*x^1 // : 9

1/9 = x^1

x = 1/9

x = 1/9

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